"EXPRESSION IN FUNCTION MAIN"a bug thtz making me to go mad?

Either you copied it incorrectly, or the book is wrong. Here is the repaired version:

#include <stdio.h>

int main(int argc, char *argv[]) {

int radius;

float area;

float pi=3.14;

printf("enter the value of radius: ");

scanf("%d",&radius);

area=pi*radius*radius;

printf("area of circle is %f\n",area);

return 0;

}

Look carefully and you'll find the differences. They're minor, for sure, but compilers and computers are dumb, relying on you to be the smart one.

Adding the return type and arguments to main is incidental, but the right thing to do.

1>First of all you must include the header file stdio.h.

2>In 6th line i.e. printf("enter the value of radius",%d); change line to:printf("enter the value of radius");(%d has been used in wrong way).

3>Since your program is starting with main therefore add return (0); in last line.And now the complete program is:

#include <stdio.h>

main()

{

int radius;

float area;

float pi=3.14;

printf("enter the value of radius");

scanf("%d",&radius);

area=pi*radius*radius;

printf("area of circle is \f%",area);

return (0);

}

Well for the work.You are commiting small mistakes.The above program is wrongly coded.The correct code is

#include<stdio.h>

#include<conio.h>

main()

{

int radius;

float area;

float pi=3.14;

printf("enter the value of radius....\n");

scanf("%d",&radius);

area=(float)(pi*radius*radius);

printf("area of circle is ....%f",area);

}

Now type it you will get correct output.

And you have a doubt why i use area=(float).....

This is a special technique that is known as "TYPE CONVERSION".

Bye

everything is correct but in printf("enter the value of radius",%d); shud be like printf("enter the value of radius"); try running this code. Before include <stdio.h>. thats it.