Solve The system for me?

I prefer using Cramer's rule and matrices when dealing with more than two variables.

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METHOD: CRAMER'S RULE & MATRICES

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The matrix for D is:

......[3 2 -1]

D = [1 -3 2]

......[2 1 -3]

Repeat the first two columns and evaluate for D.

......[3 2 -1 3 2]

D = [1 -3 2 1 -3]

......[2 1 -3 2 1]

D = (3)(-3)(-3) + (2)(2)(2) + (-1)(1)(1) - (2)(-3)(-1) - (1)(2)(3) - (-3)(1)(2) = 27 + 8 + -1 - 6 - 6 - -6 = 28

The matrix for Dx is:

........[17.8 2 -1]

Dx = [7.9 -3 2]

........[3.9 1 -3]

Repeat the first two columns and evaluate for Dx.

........[17.8 2 -1 17.8 2]

Dx = [7.9 -3 2 7.9 -3]

........[3.9 1 -3 3.9 1]

Dx = (17.8)(-3)(-3) + (2)(2)(3.9) + (-1)(7.9)(1) - (3.9)(-3)(-1) - (1)(2)(17.8) - (-3)(7.9)(2) = 160.2 + 15.6 + -7.9 - 11.7 - 35.6 - -47.4 = 168

The matrix for Dy is:

........[3 17.8 -1]

Dy = [1 7.9 2]

........[2 3.9 -3]

Repeat the first two columns anDy evaluate for Dy.

........[3 17.8 -1 3 17.8]

Dy = [1 7.9 2 1 7.9]

........[2 3.9 -3 2 3.9]

Dy = (3)(7.9)(-3) + (17.8)(2)(2) + (-1)(1)(3.9) - (2)(7.9)(-1) - (3.9)(2)(3) - (-3)(1)(17.8) = -71.1 + 71.2 + -3.9 - -15.8 - 23.4 - -53.4 = 42

The matrix for Dz is:

........[3 2 17.8]

Dz = [1 -3 7.9]

........[2 1 3.9]

Repeat the first two columns anDz evaluate for Dz.

........[3 2 17.8 3 2]

Dz = [1 -3 7.9 1 -3]

........[2 1 3.9 2 1]

Dz = (3)(-3)(3.9) + (2)(7.9)(2) + (17.8)(1)(1) - (2)(-3)(17.8) - (1)(7.9)(3) - (3.9)(1)(2) = -35.1 + 31.6 + 17.8 - -106.8 - 23.7 - 7.8 = 89.6

Evalute for x, y, and z.

x = Dx / D = 168 / 28 = 6

y = Dy / D = 42 / 28 = 1.5

z = Dz / D = 89.6 / 28 = 3.2

ANSWER: (6, 1.5, 3.2)