C programmers out there help me!!!!!!?

for

1

11

111...

program:

#include<stdio.h>

#include<conio.h>

void main()

{

int i,j,n;

clrscr();

printf("Enter the Number of lines:");

scanf("%d",&n);

for(i=0;i<n;i++)

{

for(j=0;j<=i;j++)

{

printf("1 ");

}

printf("\n");

}

getch();

}

for

1

2 3

4 5 6...

program:

#include<stdio.h>

#include<conio.h>

void main()

{

int i,j,n,count=1;

clrscr();

printf("Enter the Number of lines:");

scanf("%d",&n);

for(i=0;i<n;i++)

{

for(j=0;j<=i;j++)

{

printf("%d ",count);

count++;

}

printf("\n");

}

getch();

}

for

*

* *

* * * ...

program:

#include<stdio.h>

#include<conio.h>

void main()

{

int i,j,n;

clrscr();

printf("Enter the Number of lines:");

scanf("%d",&n);

for(i=0;i<n;i++)

{

for(j=0;j<=i;j++)

{

printf("* ");

}

printf("\n");

}

getch();

}

Gud Luck...

Here's one program that answers both parts 2) and 3) of your question:

#include <stdio.h>

#include <math.h>

int main(int argc, char *argv[]) {

int n,i,j;

char x;

if ((argc < 2) || (sscanf(argv[1],"%d,%c",&n,&x) != 2)) {

printf("\nusage: %s <height>,<symbol>\n",argv[0]);

return -1;

}

n = fabs(n);

for (i = 1; i <= n; i++) {

for (j = 0; j < i; j++) {

printf("%c",x);

}

puts("");

}

return 0;

}

As for part 1), I wonder if you've shown the pattern correctly. Something like this would make more sense:

1

23

456

etc. In which case a simple variation of my logic above is all you need. I'll let you work this one out yourself.

you could learn C# as you already suggested that your C++ is already cleared.. the two are a similar language yet c# has some extra stepped forward applications while in comparison with c++. in case you opt for to earnings this language you could somewhat learn on line only check out the under internet site for extra information -

never post this type of qus .....

just do yourself .......

ask help from your teacher .......

i'll give some hint ...

for star printing ...

========

for(k=n;k>i;k--)

printf(" ");

{for(i=0;i<n;i++)

{for(j=0;j<i;j++)

printf(" *");

printf("\n\n");}}

====for 1 just replace it by "1"

===for first one do your self ....start with i,j

then for(i=1;i<=7;i++)

plz do the rest ...

take it like a game

you need printf, and a little bit of for loops.

mix together and try yourself before taking a look at proposed solutions (alrady given here)

it's really easy and you won't go further if you can't solve this yourself

1

11

111...

program:

#include<stdio.h>

#include<conio.h>

void main()

{

int i,j,n;

clrscr();

printf("Enter the Number of lines:");

scanf("%d",&n);

for(i=0;i<n;i++)

{

for(j=0;j<=i;j++)

{

printf("1 ");

}

printf("\n");

}

getch();

}

for

1

2 3

4 5 6...

program:

#include<stdio.h>

#include<conio.h>

void main()

{

int i,j,n,count=1;

clrscr();

printf("Enter the Number of lines:");

scanf("%d",&n);

for(i=0;i<n;i++)

{

for(j=0;j<=i;j++)

{

printf("%d ",count);

count++;

}

printf("\n");

}

getch();

}

for

*

* *

* * * ...

program:

#include<stdio.h>

#include<conio.h>

void main()

{

int i,j,n;

clrscr();

printf("Enter the Number of lines:");

scanf("%d",&n);

for(i=0;i<n;i++)

{

for(j=0;j<=i;j++)

{

printf("* ");

}

printf("\n");

}

getch();

}

answer of 3

int i,j;

for(i=0;i<5;i++)

{

for(j=0;j<=i;j++){

printf("*");}

printf("\n");

}

answer of 2

int i,j;

for(i=0;i<5;i++)

{

for(j=0;j<=i;j++){

printf("1");}

printf("\n");

}

answer of 1st(if it not works then you may ask me for that)

int i,j;

for(i=1;i<=5;i++)

{

for(j=1;j<=i;j++){

printf("%d",j);}

printf("\n");

}