need help c programmers help me!!!?

Additional assignment: count the number of errors in Puneet S's solution.

Hint: even though the code is only 10 lines, there is more than one error. And that's not counting the redundant opening and closing brackets, NOR counting the non-standard definition of main().

Extra credit: find iyiogrenci's mistake (I'm not referring to the use of a system-specific extension).

Extra extra credit: find abhi r's mistake.

Extra extra extra credit: find Amit's mistake.

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Ok well..u hav got codes 4 ol da problems Except 1 prob... da 2nd prob..

Multiplication widout using *:

Multiplication is nothing but a repeated addition..so here goes da logic part of it...

Let A be da multiplicant and B be the multiplier..Eg lets multiply 3*5

#include<stdio.h>

#include<conio.h>

Void main()

{

Int A,B,i,Ans=0;

cout<<"Enter the Multiplicant:"<<endl

cin>>A

Cout<<"Enter the Multiplier:"<<endl

cin>>B

for(i=1;i<=B;i++)

{

Ans=Ans+A;

}

Cout<<"The result is:"<<Ans;

}

Fibonacci program:

#include <iostream>

using namespace std;

int main(void) {

double n; /* The number of fibonacci numbers we will print */

int i; /* The index of fibonacci number to be printed next */

double current; /* The value of the (i)th fibonacci number */

double next; /* The value of the (i+1)th fibonacci number */

double twoaway; /* The value of the (i+2)th fibonacci number */

cout << "\n\n";

cout << "How many Fibonacci numbers do you want to compute? ";

cin >> n;

if (n<=0)

cout << "The number should be positive. " << endl;

else {

cout << "\n\n\tI \t Fibonacci(I) \n\t=====================\n";

next = current = 1;

for (i=1; i<=n; i++) {

cout << "\t" << i << "\t" << current << endl;

twoaway = current+next;

current = next;

next = twoaway;

}

}

system("pause");

}

//ANSWER 1

//program to find sum of even and odd nos bet 1-100

#include<stdio.h>

#include<conio.h>

void main()

{

int i,s1=0,s2=0;

for(i=1;i<=100;i++)

{

if(i%2==0)

s1=s1+i;

else

s2=s2+i;

}

printf("\n The sum of even numbers bet1-100 is=%d",s1);

printf("\n The sum of odd numbers bet1-100 is=%d",s2);

}

int oddsum=0;

int i;

for(i=1;i<100;i=i+2)

oddsum=oddsum+i;

use the same method for even...

program to find sum of even digit and odd digit

#include<iostream.h>

void main()

{ int i,sum1=0,sum2=0;

{ for ( i=1; i<100;i=i+2)

sum1=sum1+i;}

cout<<"sum of odd no is"<<sum1<<endl;

{for {i=2;i<=100;i=i+2)

sum2=sum2+i;}

cout<<"sum of even no is"<<sum2;

}

sum of odd and even.

even=0,odd=0

for(i=1,i<=100, i++)

{

if i mod 2 =0 // even num

then even=even+i

else odd=odd+i}

print even,odd

multiplication(b*a)

mul=0;

while(i<=a)

{

mul=mul+b;

}

print mul.

Show the code you have written.

We will try to help.

d it ur self son