Who can figure out this riddle?

1 x sheep = 3

5 x cows = 50

94 x pigs = 47

100 animal and $100

80 pigs = 80x.50 = 40$

20 sheep = 20x3 = 60$

or atleast one of each animal is mandatory?

102 pigs=51

4 cows=40

3 sheep=9

______

100

I'd probably do it the easy way and buy 80 pigs and 20 sheep.

94 pigs so 94 x .50 = $47.00

5 cows so 5 x 10.00 = $50.00

1 sheep $ 3.00

-------------------

$100.00

yay!!! i solved it

Edit: but i think i was too late they already solved it :( oh well at least i tried and got it right

the answer should be :

94 pigs, 1 sheep, and 5 cows!!

wew!! that was a lot of thinking!

oops!! someoneanswered before me. i was really trying to get it first

Nevermind.

Well done, Eternal. <golf clap>

I would buy nine cows, three sheep, and 200 pigs.

Nine cows x $10.00 = $90.00

PLUS

Three sheep x $3.00

EQUALS

$99.00

AND

.5 cents x 200 pigs = $1.00

SO

$99.00 + $1.00 = $100.00

Your decimals don't fool me. :) I'm in math allll year.

It's winter break...I've done enough pre-calc all semester.

im just standing there wondering why these animals are so cheap.