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shazaam
shazaam asked in Science & MathematicsMathematics · 1 decade ago

A nice math problem... really nice!?

And by nice I mean hard! K so you got integral of arccos(cos x) from 0 to 2pi. Can anyone help please? Thank you.

Update:

How do I solve it?

3 Answers

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  • Goldi
    1 decade ago
    Favorite Answer

    y=arccos(cos x)

    =x from 0 to pi

    =2pi-x from pi to 2pi

    ans:19.76

  • napoleon9th
    Lv 4
    1 decade ago

    Well, you could start by simplifying "arccos(cos x)"... I get 39.48 as the answer.

    Edit: oops, i missed the codomain of arccos and i was wrong. 39.48 is not the answer. :">

    Goldi's answer is also a bit off: it should be pi^2 ~= 9.87...

    Source(s): i'm a math geek ^^
  • Anonymous
    1 decade ago

    Answer is 142.638

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