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Dilution Ratios With HC-110?

I'm using HC-110, from concentrate, which requires the use of dilutions to get a desired effect. I'm familiar with dilution B, a 1:31 solution, but I'm not sure how to get this dilution from the stock solution. To get the stock, you take 1 part concentrate to 3 parts water, or 1:3. Then add that 1:3 solution to a 1:7 of water. This is dilution B. My question is, how does this work out, mathematically speaking? More specifically, how would I solve this on a calculator, or in my head? (I'm not sure how you get 1:31 from adding 1:3 and 1:7. Thanks for any help.

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  • 1 decade ago
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    The math will work out if you look at the concentration in the solution, not the mixing ratios. Mixing 1 part of developer in three of water gives you a solution that is 1/4th developer. Mix that with 7 times as much water and you have a dilution of 1/32nd, which is dilution B.

    But the short answer is, there is really no point in storing partial dilutions because they don't keep as well as the concentrated developer. Use a syringe or lab graduate to precisely measure small amounts and mix dilution B straight from the bottle. The only rationale for the two-step dilution is that it gives more consistent results if you're trying to mix up half a pint using kitchen measuring tools.

    Source(s): used to do this, many years ago...
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