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How Do you do this Chemistry?
CaCN2 + 3H2O - CaCO3 + 2NH3 .
How much CaCO3 is produced upon reaction of 45 g CaCN2 and 45 g of H2O?
1. 250 g
2. 38 g
3. 19 g
4. 750 g
5. 28 g
6. 83 g
7. 56 g
Consider the reaction
N2 + 3H2 - 2NH3 .
How much NH3 can be produced from the
reaction of 74.2 g of N2 and 14.0 moles of H2?
1. 5.62 × 1024 molecules
2. 3.19 × 1024 molecules
3. 1.26 × 1025 molecules
4. 1.59 × 1024 molecules
5. 1.69 × 1025 molecules
In the reaction below, 22 g of H2S with excess O2 produced 7 g of sulfur.
?H2S + ?O2 - ? S + ?H2O.
What is the percent yield of sulfur? Answer
in units of %.
Consider the following reaction:
CaCN2 + 3H2O - CaCO3 + 2NH3
105.0 g CaCN2 and 78.0 g H2O are reacted.
Assuming 100% efficiency, which reactant is in excess and how much is leftover? The molar mass of CaCN2 is 80.11 g/mol. The
molar mass of CaCO3 is 100.09 g/mol.
1. CaCN2; 70.8 g left over
2. H2O; 70.8 g left over
3. H2O; 10.7 g left over
4. CaCN2; 7.20 g left over
5. CaCN2; 10.7 g left over
6. H2O; 7.20 g left over
Consider the following reaction.
N2 + 3H2 - 2NH3 .
28.0 grams of N2 and 5.04 grams of H2 are
reacted, producing 17.8 grams of NH3. What
is the percent yield?
1. 34.0%
2. 14.7%
3. 62.9%
4. 52.4%
5. Not enough information is given.
6. 84.0%
7. 191%
1 Answer
- 1 decade agoFavorite Answer
First question is 7. 56 g.
45g(1 mol/18g)=.5625 mol(1 mol/1mol)=.5625 mol
.5625 mol(100g/1 mol)=56.25 grams
I think?