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how to find pressure 2 using combined gas law?
i can't figure out how to solve this problem using the combined gas law(P1XV1/T1=P2XV2/T2):
A 5.0-L air sample at a temperature of -50*C has a pressure of 800 mm Hg. What will be the new pressure if the temperature is raised to 100*C and the volume expands to 7.0 L?
3 Answers
- skipperLv 71 decade agoFavorite Answer
P1V1/T1 = P2V2/T2
800 mm Hg x 5.0 L / 223 K = P2 x 7.0 L / 373 K
P2 = 800 mm Hg x 5.0 L x 373 K / (223 K x 7.0 L) = 955.8 mm
P2 = 956 mm Hg
- 5 years ago
2.0 x 10.0 / 293 = P2 x 10.0 / 318 (temperature must be in kelvins, so 273 is added to the degrees celsius) P2 = 2.2 atm this makes sense because as temperature increases, pressure increases
