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Need help with chemistry homework please. ?
33.5 g of an unknown metal, at a temperature of 99.0 C is mixed with 100.0 g of water at a temperature of 22.0 C. The resulting mixture reached a maximum temperature of 26.5 C. What is the specific heat of the metal? If you could be kind enough to show me the formula I will be forever grateful. Thanks
1 Answer
- Dr.ALv 71 decade agoFavorite Answer
specific heat water = 4.18 J/g°C
heat lost + heat gained = 0
33.5 x specific heat ( 26.5 - 99.0) + 100.0 x 4.18 ( 26.5 - 22.0) = 0
- 2415.35 x specific heat + 1881 = 0
specific heat = 0.779 J/g°C