Sinusoidal Wave Question?

The amplitude is 3V.

The peak-to-peak value is 6V.

The period (T) is approximately 4ms

The frequency is 1/T = 1/.004 = 250Hz

The phase is a little more difficult. I'd estimate that the first zero-crossing is about 0.3ms. To calculate the phase offset:

φ = (0.3/4.0)*360° = 27°

Since this is approximately a sine wave, but at t=0 the value is negative, the phase is also negative, so:

φ = -27° = -27*pi/180 = -.471radian

V = 3*Sin(2*pi*250*t - .471)

P.S. the URL had a lot of "sp aces" in it that needed to be removed??

Take a better Digital oscilloscope with all the digital on-screen readout windows available which tells you all that and more - RMS, P-P, Period (if more than two cycles on the screen), Frequency, FFT harmonic content, Delta time measurements using cursors etc - everything about a waveform.

However - a Phase measurement requires 2 (two) wave forms.... measuring the phase difference between the reference (1st trace) and the second wave form on the 2nd trace.

That's how I go about it.

amplitudeA = 3V , peak-to-peak value = 6 V,

period = 4 ms, frequency f= 250Hz

for the phase you must mesure precisely but it must be around

p = 0.3 ms

so the waveform expression is f(x) = A sin(2Pi.f.x - p)

Your URL doesn't lead anywhere.