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College calc question?

On the planet Maximillian live Sprogs and Graks. Initially there were 2400 sprogs and 300 Graks. The population of Sprogs doubles every 14 years and that of Graks doubles every 7 years.

how do i find the number of years it would take so that there are as many sprogs and graks?

work it out please, so i can do the rest, thank you :]

3 Answers

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  • 1 decade ago
    Favorite Answer

    This can actually be done without any equations at all, since the problem is set up to make it easy. Every 14 years, the Sprog/Grak ratio (originally at 8:1) is cut in half because while the Sprogs doubled, the Graks quadrupled. So it'd take three 14-year cycles to do this, or 42 years.

    However to set this up on a more general level:

    s = 2400 2^(t/14)

    g = 300 2^(t/7)

    s = g

    2400 2^(t/14) = 300 2^(t/7)

    8 = 2^(t/7 - t/14)

    8 = 2^(t/14)

    3 = t/14

    t = 42

    The problem ultimately doesn't involve calculus at all. It's just a matter of using logarithms.

  • Anonymous
    1 decade ago

    Calculus not required

    2400(2)^(t/14) = 300(2)^(t/7)

    8*(2)^(t/14) = (2)^(t/7)

    8 = (2)^(t/7) / (2)^(t/14)

    8 = 2^(t/7 - t/14)

    8 = 2^(t/14)

    ln 8 = ln 2^(t/14)

    ln 8 / ln 2 = t/14

    t = 14* ln 8 / ln 2

    t = 42 years

  • 1 decade ago

    This is how we do it in Ireland;

    Divide the 300 Graks by the 2400 sprongs.

    The answer (plus a random number) is 200.

    Source(s): Got it?
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