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Physics heating and melting question?
100g of ice at -15 degree C is placed in 200g of water at 25 degree C. What is the final temperature when thermal equilibrium is reached?
Specific heat capacity of water is 4200J/kg.K
Specific heat capacity of ice is 2100J/kg.K
Specific latent heat of ice is 340 000J/kg
How do you do this question? Thanks for the help!
1 Answer
- Anonymous1 decade agoFavorite Answer
First you have to heat up the ice to 0 degrees. This takes 2100J/kg/K * 100g * 15degrees = x Joules.
Then you have to melt the ice. This takes 340 000J/K * 100g = y Joules.
This energy is extracted from the water at 25 degree. Now use 0 degree C as a reference temperature. The melted ice has a surplus energy of zero, because it is at 0 degree C. The water has a surplus energy of 4200J/kg/K * 200g * 25degrees - x Joules - y Joules.
Divide this surplus energy over the 300g of water you now have and you'll find the temperature of the water above the reference temperature.