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Equilibrium reactions?
The gas arsine, AsH3, decomposes as follows.
2 AsH3(g) reverse reaction arrow 2 As(s) + 3 H2(g)
In an experiment at a certain temperature, pure AsH3(g) was placed in an empty, rigid, sealed flask at a pressure of 392.0 torr. After 48 hours the pressure in the flask was observed to be constant at 488.0 torr.
(a) Calculate the equilibrium pressure of H2(g).
(b) Calculate Kp for this reaction.
1 Answer
- TheOnlyBeldinLv 71 decade agoFavorite Answer
488.0 = 3x + (392 - 2x)
x = 96; so pressure of H2 = 288 torr, pressure of AsH3 = 200 torr
Kp = P(H2) ^3 / P(AsH3) ^ 2 = (288)^3 / (200)^2 = 597.2
