Need Chemistry help - Balancing chemical equations?

Your balanced equation is this:

Al(NO3)3 + 3NaOH -> Al(OH)3 + 3NaNO3

Since there are three hydroxide ions in Al(OH)3, you need to start with three OH- ions. You would need 3 NaOH.

If you actually did this, it would be more likely to produce a precipitate that dissolved as more NaOH was added. The reaction is as follows:

Al(NO3)3(aq) + 4NaOH(aq) --> 4Na+ + Al(OH)4^- + 3NO3^-

or, the net ionic equation is

Al^3+ + 4OH- --> Al(OH)4^-

You need to end up with the same number of each molecule on either side of the equation.

I would start with the aluminum hydroxide in the product. If you look at OH- there are now 3 of them, so there has to be 3 sodium hydroxide in the reactants to even out the number of -OH molecules on either side of the equation, giving you

Al(NO3)3 + 3NaOH -> Al(OH)3 + NaNO3

Now you have three sodium molecules in the reactants that have to be accounted for in the products, so you have

Al(NO3)3 + 3NaOH -> Al(OH)3 + 3NaNO3

Now there are an equal number molecules of each in the reactants and products and the equation is balanced.

Al(NO3)3 + 3 NaOH -> Al(OH)3 + 3 NaNO3

Iron is Fe, Sulfur is S, Iron (II) Sulfide is FeS you need to think of the reaction is easy - a million atom of each: Fe + S -> FeS even if, organic Sulfur likes to combine jointly into molecules - S8, at a similar time as Iron in organic style will thankfully exist as individual atoms. so which you're able to truly could desire to do a larger batch: 8Fe + S8 -> 8FeS Your different issues are probably to be comparable.

heres a website that should help you:

http://www.webqc.org/balance.php