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Friction Coefficient (This is real life not homework)?
Is the friction of dragging 1100 feet of chain weighing a total of 3000 lbs, less or more than the friction of dragging a single block of iron (approximately cubical) of the same weight?
I live on my boat and need to find an alternative to a mooring which is what most boats use if they intend to stay in one place for a long time. I move from Key West to Key Largo six months at a time. I can't make two moorings because someone would simply use the mooring I am not using. One can not claim property left on the sea floor.
The best mooring for my boat is a 3000 lb. block of iron. The problem is, I can't pick that up and put it on the deck while traveling between. To solve that problem, I want to use a length of chain as the weight. 1100 feet of 1/2 chain weights about 3000 lbs. I can use my chain windlass to bring the whole length into the chain locker. This brings the question.
Is the friction of dragging 1100 feet of chain weighing a total of 3000 lbs, less or more than the friction of dragging a single block of iron (approximately cubical) of the same weight?
It will be drug through soft soil saturated by sea water. But one can assume any surface for calculating friction as both the block and the chain would be drug across the same.
Thank you
Jerry
2 Answers
- Benjamin NLv 41 decade agoFavorite Answer
Well, since the surface area of the chain is larger, I'd say the chain would create more drag. Try not to kill too much coral.
- Anonymous5 years ago
You wish to stop your car from a certain speed. The maximum acceleration that you can get is given by:- coefficient of friction * g So take g as about 10 m/s ^2 If you know that the surface gives a coefficient of friction of 1 then that is the maximum acceleration and you can easily know the braking distance from any speed. eg as V^2 = 2as then s = v^2 / 2a and if v= 30m/s , and a = 10 ( coefficient of friction = 1) then s = 900/20 = 45 m If you have good bitumen and fair tyres then the coefficient might be 0.6 so your braking distance has increased to 900/12 = about 80 m On a wet road with a coefficient of about 0.3 then the braking distance is now about 900/6 = 150m and on ice with a coefficient of about 0.1 you have a braking distance of 450 m on the level from this speed. And if you want to survive you really do need to know how far you will go before being able to stop. In other cases it can show the maximum slope that a body can be on without sliding. It determines whether a given knot will slip or hold. And many related phenomenae.