Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
HELP WITH CHEMISTRY PLEASE!!! (college level)?
1) If 710. mL of 0.04868 M aqueous NaBr and 1.134 g of gaseous Cl2 are reacted stoichiometrically according to the equation, how many mol of gaseous Cl2 remained?
2 NaBr(aq) + Cl2(g) → 2 NaCl(aq) + Br2(l)
2) If 570 mL of 0.0228 M aqueous BaCl2 and 860 mL of 0.00534 M aqueous Al2(SO4)3 are reacted, what mass (g) of solid BaSO4 is produced?
Al2(SO4)3(aq) + 3 BaCl2(aq) → 2 AlCl3(aq) + 3 BaSO4(s)
2 Answers
- 1 decade agoFavorite Answer
1)
.710 L ( 0.04868 M) = .0346 mol NaBr
1.134 g Cl2 (1 mol / 70.9 g) = .016 mol Cl2
For 1 mol Cl2, 2 mol NaBr react.
.016 * 2 = .032 mol NaBr react with .016 mol Cl2
THERE IS NO Cl2 REMAINING, THERE IS NaBr REMAINING.
.0345 - .032 = 0.0025 mol NaBr remain.
2)
.570 L (.0228 M) = .013 mol BaCl2
.860 L (.00534 M) = .0046 mol Al2(SO4)3
For 1 mole Al2(SO4)3, 3 mol BaCl2 are needed.
.0046 * 3 = .014 mol Al2(SO4)3 needed
BaCl2 is limiting.
.013 mol BaCl2
The ratio of BaCl2 and BaSO4 is 1:1
So, .013 mol of BaSO4 are produced.
.013 mol BaSO4 ( 233.4 g / 1 mol ) =
3.034 grams of BaSO4
Source(s): =] My Brain. - ?Lv 45 years ago
it somewhat is actual no longer common. it somewhat is generally one in all of the main puzzling time-honored education training for faculty youngsters who're no longer technology majors to bypass. despite if, in case you have already got an affinity for chemistry, then it probable is purely no longer so puzzling for you. it somewhat is going to in all probability nonetheless be time eating and require a good style of artwork inspite of the incontrovertible fact that.