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Third degree MacLaurin polynomial?
For f(x) = (e^2x) + 3x
I got 1 + 5x + 2x^2 + (4/3)x^3
Is this correct?
3 Answers
- FLGatorLv 41 decade agoFavorite Answer
you are correct
C1 = f(0) = 1
C2 = f'(0) = 5
C3 = f''(0) / 2! = 4 / 2 = 2
C4 = f'''(0) / 3! = 8 / 3! = 8 / 6 = 4/3
- Anonymous4 years ago
GWC math185? i prefer help too. my difficulty is permit F(x)=essential (from 0 to x) of e^(-2t^4)dt. discover the MacLaurin polynomial of degree 5 for F(x)? Use this polynomial to estimate the fee of the essential from 0 to 0.19 The MacLaurin polynomial of degree 5 may be f(0) + f'(0)x + f''(0)/2! x^2 + f'''(0)/3! x^3 + f^(4) (0)/4! x^4 + f^(5) (0)/5! x^5 f'(x) = e^(-4x)^4 accompanied from the elementary theorem of calculus. So f(0) = essential[0 to 0] = 0 f'(0) = e^(-4*0)^4 = 0 f'(0) = d[e^(-4x)^4]/dx at x=0 etc. ;( stupid essential !!!
