how to factorise 100x^2- 80x + 16?

Question

is it infactorable? how will I know whether it can be factored or not?

thanks in advance.

Pi R Squared · Accepted Answer

Hi,

100x² - 80x + 16 =

Factor out the GCF of 4 first.

4(25x² - 20x + 4) =

Now factor the trinomial.

4(5x - 2)(5x - 2) or 4(5x - 2)² <==ANSWER

I hope that helps!! :-)

Scorpio9 · Answer

Answer :

It is very factorable! See the solution below :

100x^2 - 80x + 16
= (10x - 4)(10x - 4)
= (10x - 4)^2

Jun Agruda · Answer

100x² - 80x + 16 = 0
x² - 4/5x = - 4/25
x² - 2/5x = - 4/25 + (- 2/5)²
x² - 2/5x = - 4/25 + 4/25
(x - 2/5)² = 0
x - 2/5 = 0

Answer: 4(5x - 2)² OR 4(5x - 2)(5x - 2)

Checking:
= 4([5x - 2][5x - 2])
= 4(25x² - 10x - 10x + 4)
= 4(25x² - 20x + 4)
= 100x² - 80x + 16

An ESL Learner · Answer

100x^2 - 80x + 16
= 4(25x^2 - 20x + 4)
= 4(25x^2 - 10x - 10x + 4)
= 4[(25x^2 - 10x) - (10x - 4)]
= 4[5x(5x - 2) - 2(5x - 2)]
= 4(5x - 2)(5x - 2)
= 4(5x - 2)^2

gudspeling · Answer

100x² - 80x + 16
= 4(25x² - 20x + 4)
= 4((5x)²-2×5x×2+2²)
= 4(5x-2)²

koolnishant93 · Answer

100x^2 - 80x +16
= (10x - 4)^2

:)

Como · Answer

4 ( 25 x ² - 20 x + 4 )

4 ( 5x - 2 ) ( 5x - 2 )

4 ( 5x - 2 ) ²

Moise Gunen · Answer

(10x-4)^2

James · Answer

4(5x-2)^2

Anonymous · Answer

(10x-4)(10x-4)

=D

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how to factorise 100x^2- 80x + 16?

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