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3tan^2θ + tanθ = 4 and cos^2θ = 5 + 8 cos θ?
I'm sure if someone could explain it to me I would get it but my teacher has a heavy accent and I can't understand too well.
Again the problems are
3 tan^2 θ + tan θ = 4
and
cos^2 θ = 5 + 8 cos θ
1 Answer
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- alisabyrneLv 51 decade agoFavorite Answer
just pretend
3x^2+x-4=0
(3x+4)(x-1)=0
3 tan θ + 4 =0 tanθ =-4/3
tan θ -1= 0 tan θ = -1
Look at your chart to find theta
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