2.I am a three digit number. My tens digit is five more than my ones digit. My hundreds digit is eight less t?

Let the number be abc.

Then we have 4 statements:

(1) b = c + 5

(2) a = b - 8

(3) 0 =< b,c < 10 (since they are each single digits)

(4) 0 < a < 10 (since it is a 3 digit number, hence a is non-zero)

From (1), (2), we get:

(5) a = b - 8 = c + 5 - 8 = c - 3

From (4), (5):

c - 3 > 0 => c > 3

From (1), (3):

c + 5 < 10 => c < 5

Since 3 < c < 5, hence c = 4.

Using (1), (5), we get:

b = 4 + 5 = 9

a = 4 - 3 = 1

Hence the number is 194.

Nice riddle/question.

Let the number be xyz.

From the given statement: I deduce the fact below.

(1) y = z + 5

(2) x = y - 8

(3) 0 = < y,z < 10 (Because they are single digit each)

(4) 0 < x < 10 (so far the numbers is a 3 digit, hence it is a non - zero numbers)

From (1), (2), we get:

y = z + 5 ........ (1)

x = y - 8 ......... (2)

From (2)

x = y - 8

y = x + 8 ............. equation(5)

By equating equation (1) and equation (5)

y = y

z + 5 = x + 8

x = z + 5 - 8

x = z - 3 ........................ equation (6)

From (4), (6):

z - 3 > 0

∴ z > 3

Hence, z > 3

From (1), (3):

z + 5 < 10

z = < 10 - 5

∴ z < 5

Since 3 < z < 5, hence z = 4.

Using (1), (2), we get:

y = 4 + 5 = 9

x = 9 - 8 = 1

∴ x = 1, y = 9, z = 4

Since the number is xyz

Hence the number is 194.

I am a 3-digit number

194

'4'+5=9

(if we consider the one's digit to be 1)

9-8=1

therefore, ans=194

I Am Three

lets see....

194

194

Haha Thats Good = ] Got any more?!

491.?

149.

Good question.