Pls help on Integration...?

Integrate (2x-1)dx

will give you

(2x^2)/2-1x+c

(2x^2)/2 -1x + c (remember the constant)

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Introduction to integration:

The rule for differentiation is given as:

y=x^n > dy/dx=nx^n-1

Reversing this gives you the rule for integration:

Integrating x^n with respect to x gives (x^n+1)/(n+1) + c

You may find it helpful to remember the rule as:

"Add 1 to the power and divide by the new power, then add a constant."

So 1 will go to 1x

So 1^2 will go to (1^3)/3

So 1^3 will go to (1^4)/4

and so on....

REMEMBER THE ARBITRARY CONSTANT C

∫x^n(dx)=(x^(n+1))/(n+1)+c

∫(2x-1)dx=

((2x^2)/2)-((1x^1)/1)=

(x^2)-x+c