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Eurgh-Sire-Awe
Eurgh-Sire-Awe asked in Science & MathematicsMathematics · 1 decade ago

Math graph question and differentiation.?

what is the dy/dx of the graph y=2^x?

4 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    Try with d(a^v)/dx = a^v * lna * dv/dx, then a = 2; v = x

    so, y' = dy/dx = 2^x * ln2 * dx/dx = 2^x * ln2

  • ?
    1 decade ago

    2

  • anwar
    Lv 6
    1 decade ago

    y=2^x

    take ln of both sides

    lny =xln2

    now

    1/y dy/dx =ln2

    and dy/dx=yln2

    ..............=2x^2 ln2

  • manu_0623
    1 decade ago

    y = 2^x

    ∂y/∂x = y’ = 2^x ln 2 --- (Answer)

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