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Physics Electrostatics?
A .50kg cart with a metal sphere, charged q = +2.0 x 10E-5 starts at rest 1m to the right of a fixed sphere with positive charge +3 x 10E-4. The cart is 9m to the left of a sphere with charge -3 x 10E-4. The cart is released. How fast is the cart moving when it is 1m from the negatively charged sphere on its right.
1 Answer
- 1 decade agoFavorite Answer
Use potential and kinetic energy. The change in potential energy will equal the kinetic energy.
k*q*q1(1/r1f - 1/r1i) + k*q*q2(1/r2f - 1/r2i) + 0.5*m*v^2 = 0
-0.5*m*v^2 = k*q(q1(1/r1f - 1/r1i) + q2(1/r2f - 1/r2i))
-0.5*m*v^2 = (9*10^9)(2*10^-5)((3*10-4)(1/9 - 1/1) + (-3*10^-4)(1/1-1/9))
-0.5*m*v^2 = -96 joules <--- that's the change in potential energy
solve for v
v = (96/(0.5*m))^0.5
v = (96/(0.5*0.5))^0.5
v = 19.6 m/s
hope that helps!
