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A sample of gas has an initial volume of 34.3 L at a pressure of 1.5 atm.?

If the sample is compressed to a volume of 13.5 L and maintained at a constant temperature, what will its atm pressure be?

2 Answers

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  • 1 decade ago
    Favorite Answer

    Assuming no gas is lost to this process,

    from one state to the next,

    there exists two states 1,2, such that:

    (P1 x V1) / T1 = (P2 x V2) / T2

    Given temp. is constant, T1 = T2,

    they cancel from the equation

    ==> (P1 x V1) = (P2 x V2)

    Solving for P2:

    P2 = (P1 x V1) / V2

    Substituting given values:

    P2 = (1.5 atm x 34.3 L) / 13.5 L

    = 3.81 atm

    (at 3 sig. figs.)

    Source(s): self
  • Dr.A
    Lv 7
    1 decade ago

    p1V1 = p2V2 ( Boyle's law)

    1.5 x 34.3 = p2 x 13.5

    p2 = 3.8 atm

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