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Help with calculus questions please?
1. Find the gradient of the curve y = 6 + 2x - 3x^2 at the point where x = 4
2. Find the value of the gradient function of the curve f(x) = 3x^2 + 2x +1 when x = 2
3. Find the x-coordinates of the points on the graph of y = 4x^2 - 2/3 x^3
4. Consider the function f (x) = x^3 - 3x^2 - 9x + 1. Find the x values of the points where this function has zero gradient.
5. Find the point on the curve y = x^2 + 4x where the gradient is 10.
6. Find the equation of the tangent to y = x^2 + x-1 at the point (3,11)
If anyone could help with these questions.. I am not sure how to work them out. Thanks :)
1 Answer
- qwertLv 51 decade agoFavorite Answer
remember that the gradient or slope of the tangent of y = f(x) is the
derivative dy/dx
evaluate dy/dx at the required point to get the slope
for the first question
dy / dx = 2 -6x
now substitute x = 4 to get gradient = -22
Source(s): an example on finding the tangent to a curve (implicit form) http://rbmix.com/problem/math/tangent/tangent.html
