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? asked in Science & MathematicsMathematics · 1 decade ago

Hard probability question?

Ok, this is a probability question that one of my friends pondered me and I wasn't able to figure it out after half heartedly working on it for a LONG time. So I was wondering if any of you could enlighten me ^_^... here goes nothing :P

You have 2 six sided dice with removable faces. You remove each face off of both dice and then randomly apply the faces back on again [so you could have the dice looking like 1, 1, 2, 3, 4, 4 and 2, 3, 4, 5, 5, 6, 6 etc. etc.]... What is the probability of rolling a 7?

Thanks!

Update:

Edit: Okay, you have TWO six sided dice and you add the numbers rolled on each of them. The thing that makes this problem mind boggling though is the sheer number of dice combinations you can have, there's some trick to the problem I know.. :P yeah it's really hard

Update 2:

Edit again, Haha, sorry, In my example that's not the set die thing. The point of the problem is the die every time is completely different so it just *could* be one of many things. very confusing...

Update 3:

If it helps anyone, I looked back through my notebook and I found a few things about this problem.. I did these by complete brute force method in hopes of finding a pattern with combinations or the like, but alas, no luck :P... but one of you may see a pattern. I've done the probabilities for theoretical 2 sided, 3 sided, and 4 sided dice. Doing 5 sided brute force would be hellish, and 6 sided would just defeat the point of finding the trick, not to mention it would take a ridiculous amount of time xD.. so anyways. For a 2 sided die [Btw, all of these start with 0, then go up, so 2 sided die has 0 and 1 on it.], the probabilities are

1/8=0

6/8=1

1/8=2

For a 3 sided die, the probabilities are:

1/15=0

4/15=1

5/15=2

4/15=3

1/15=4

For 4 sided dice, the probabilities are:

1/28=0

4/28=1

5/28=2

8/28=3

5/28=4

4/28=5

1/28=6

Meh, gonna go check combinations again. right now though it just seems quite the ridiculous problem :P

5 Answers

Relevance
  • ET
    1 decade ago
    Favorite Answer

    Possibilities:

    1,1 2,1 3,1 4,1 5,1 6,1

    1,2 2,2 3,2 4,2 5,2 6,2

    1,3 2,3 3,3 4,3 5,3 6,3

    1,4 2,4 3,4 4,4 5,4 6,4

    1,5 2,5 3,5 4,5 5,5 6,5

    1,6 2,6 3,6 4,6 5,6 6,6

    Only 1,6 2,5 3,4 4,3 5,2 6,1 total as a 7.

    So there are 36 possibilities and 6 combos. So the probability is 6/36 or 1/6 or .16666~

    Hoped I helped!

  • Anonymous
    1 decade ago

    it all depends

    if you have all the 1's 3's 4's on one of the dice then the probability would be chance of olling a 1 on 1 dye and rolling 5 on other, rollinlg 4 on 1 dye rollinlg 2 on the other. both dye are independt of each other so it all depends on placement of the numbers. if you gave a certain set of numbers on each dice i could answer it for you however.

    Source(s): memory
  • Anonymous
    1 decade ago

    you cant roll a seven! its only six sided!

    unless your talking about adding up the numbers you roll...thennnn...

    1-2 ...1

    1-3 ...2

    1-4 ...3

    WOAH! wait a minute how can you have 7 numbers on a six sided dice!? the second pair of numbers has 7 numbers! you said six sided dice! whattt!? major confusion.

  • R B
    1 decade ago

    Sorry I don't know the answer, but very cool question.

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  • brianua13
    1 decade ago

    1-6;1-6;1-6;1-6;2-5;2-5;3-4;4-3;4-3;

    9/36 or 1/4

    wait yeah that doesn't make sense

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