Can anyone help me do this (4a - 7b)^2?

There is a rule where

(a + b)^2 = a^2 + 2ab + b^2.

This is much more efficient than FOIL in this case.

Applying it to this:

(4a - 7b)^2 = (4a)^2 + 2(4a)(-7b) + (-7b)^2

= 16a^2 - 56ab + 49b^2

Best of luck in your future endeavors.

FOIL it out.

This is how you would expand it:

(4a-7b)^2

Expand the square:

(4a-7b)(4a-7b)

This isn't necessary, but I find it easier to use addition signs:

(4a+ -7b)(4a+ -7b)

FOIL-multiply the first terms, outer terms, inside terms, last terms:

(4a x 4a)+(4a x -7b)+(-7b x 4a) + (-7b x -7b)

Results from FOIL-ing:

16a^2 + -28ab + -28ab + 49b^2

Combine like terms:

16a^2 + -56ab + 49b^2

Put the subtraction signs back:

16a^2 - 56ab + 49b^2

And since there is no common multiple of 16, 56, and 49, this is as simple as it gets.

( 4a - 7b ) ( 4a - 7b )

16 a^2 - 56 ab + 49 b^2

u cnt simplify but you can expand

Difference of two squares:

(4a - 7b)(4a + 7b)

(4a - 7b)(4a - 7b)

16a^2 - 28ab - 28ab + 49b^2

16a^2 - 56ab + 49b^2.

All you have to do is just foil it like

16a^2-56ab+49b^2

its already simplified to the lowest it can go

or foil which is

(16a^2-56ab+49b^2)

(4a-7b)(4a-7b)

FOIL

16a^2-28ab-28ab+49b^2=

16a^2-56ab+49^2

Idk if its right