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ALGEBRA II HONORS QUESTION? DO THESE THREE PROBLEMS HAVE SOLUTIONS?
1) 3x + 2 - x = 2x + 1
2) 5z - 3 = -3 + 4z
3) 5t + 4 = 3(2 - t) + 8t
Thank you so much!
4 Answers
- VFBundyLv 61 decade agoFavorite Answer
1) 3x + 2 - x = 2x + 1
No solution
2) 5z - 3 = -3 + 4z
z = 0
5t + 4 = 3(2 - t) + 8t
No solution
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- 1 decade ago
3x + 2 - x = 2x + 1
3x-x+2 = 2x+1
2x+2 = 2x+1
-1 -1
2x+1 = 2x
-2x -2x
1=0
no solution
5z - 3 = -3 + 4z
+3 +3
5z = 0+ 4z
-4z -4z
z=0
5t + 4 = 3(2 - t) + 8t
5t+4 = 6-3t + 8t
5t+4 = 6+5t
-4 -4
5t = 2+5t
-5t -5t
0=2
no solution
:)
- 1 decade ago
1) (3x - x) + 2 = 2x + 1
2x + 2 = 2x+1
2 = 1 # not possible
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2) 5z - 3 = -3 + 4z
5z - 4z = -3 +3
z = 0
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3) 5t + 4 = (6 - 3t) +8t
5t +4 = 6 + 5t
4 = 6 # (not possible)
Source(s): -
