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im confused about this can someone help?

the question was:

If there were no air drag, how fast would drops fall from a cloud 1.6 kilometer above the Earth's surface?

what i did is i tried to find the displacement and i got 15.68 somehow and now i think the displaement didn't really matter in this problem.

can sombody help explain this problem?

Update:

i tried converting to m first then i divided both by 2 getting

2d=at^2 and then i divided both by the acceleration which i assumed to be gravity (9.8) after that i had 2(1600)/9.8=t^2 and to get rid of the exponet i rooted both sides and got 326.5

it was a mess and it was wrong am i even in the right direction??

1 Answer

Relevance
  • 1 decade ago
    Favorite Answer

    D = 1/2 A T^2

    Calculate T.

    V = AT

    Calculate V.

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