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Help me with this stupid physics question, please?
A guy with a mass 65 kg skis down a frictionless hill that is 5.0 m high. At the bottom of the hill the terrain level out . As the man reaches the horizontal section, he grabs a 20-kg backpack while still moving and skiss of 2.0 m high ledge. at what horizontal distance from the edge of the ledge does the man land?
1 Answer
- zee_primeLv 61 decade agoFavorite Answer
When he grabs the backpack his speed is SQR(2 x 9.8 x 5)=9.9m/s, so his momentum is 65 x 9.9=643.5 kg.m/s, so after he grabs the backpack his momentum will be the same and his speed will be 643.5/(65+20)=7.57 m/s. It takes SQR(2s/a)=SQR 2 x 2/9.8)=0.64 sec to fall 2m, and in this time he will have travelled horizontally 0.64 x 7.57=4.84 metres from the ledge.