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2 Answers
- 1 decade agoFavorite Answer
2 KClO3 =====> 2 KCl + 3 O2
De esto deducimos que por cada 2 moles de KClO3 obtenemos 3 moles de O2
Peso de 1 mol de KClO3 = 19 + 17 + 8x3 = 60 g/mol
Peso de 1 mol de O2 = 16 g/mol
Si 16 g de O2 =========> son formados por 60 g de KClO3
4 g de O2 =========> formados por x = 15 g de KClO3
Necesitas 15 g de KClO3
- crisLv 61 decade ago
2KClO3------------- 2KCl +3O2
Segun la ecuacion se tienen
K=39*2+Cl35.5*2+O16*6 = 245 grs de 2KClO3
3O2 = 16*6 = 96 grs luego
245 grs KClO3------------------ 96 grs O2
X-------------------------------------- 4.5 grs
X = 11.48 grs de KClO3