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How many grams produced in solution?

If 5.45g of copper was reacted with 20.0mL of 16M Nitric acid (HNO3), how many grams of Cu(NO3)2 will be produced in solution?

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  • Dr.A
    Lv 7
    1 decade ago
    Favorite Answer

    moles copper = 5.45 / 63.546 g/mol=0.0857

    moles HNO3 = 0.0200 L x 16 M=0.320

    Cu + 2 HNO3 = Cu(NO3)2 + H2

    HNO3 is in excess

    moles Cu(NO3)2 = 0.0857

    mass Cu(NO3)2 = 0.0857 x 187.56 g/mol=16.1 g

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