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nintendogamer91
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How many grams produced in solution?
If 5.45g of copper was reacted with 20.0mL of 16M Nitric acid (HNO3), how many grams of Cu(NO3)2 will be produced in solution?
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- Dr.ALv 71 decade agoFavorite Answer
moles copper = 5.45 / 63.546 g/mol=0.0857
moles HNO3 = 0.0200 L x 16 M=0.320
Cu + 2 HNO3 = Cu(NO3)2 + H2
HNO3 is in excess
moles Cu(NO3)2 = 0.0857
mass Cu(NO3)2 = 0.0857 x 187.56 g/mol=16.1 g
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