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Jim
Lv 7
Jim asked in Science & MathematicsPhysics · 1 decade ago

Physics - Magic Trick?

A magician pulls a tablecloth from a table that has a 0.85 kg vase on it, half-filled with water. If he pulls in such a manner that the tablecloth is removed at the minimum speed necessary to keep the vase and its contents stationary - with what force must he pull? (answer to 1 decmal place)

additional info:

----------------------

vase capacity = 1.0 L

coefficient of kinetic friction between table and tablecloth = 0.3

coefficient of static friction between vase and tablecloth = 0.6

2 Answers

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  • 1 decade ago
    Favorite Answer

    m=0.85+ 0.5liter *1kg/liter

    Fn=Normal force down

    F₁ = initial force

    F₂ = constant force

    The force you pull with will have to be equal to or greater than the maximum friction force.

    The initial force (F₁) to overcome the initial static friction is going to have to be greater then the constant force (F₂) after things start moving.

    I don't really know which one they want.

    The basic equation is

    Fnet=ma

    F-Ffriction = ma = 0

    F only has to be equal to or greater than the maximum kinetic friction force. The vase does not have to accelerate relative to the table cloth. It only has to move at a constant speed relative to it.

    As you pull with a greater and greater force F, Ffriction will grow and grow and will reach a maximum according to the equation F=μFn

    To find F₁ and F₂

    Ffriction=μ•Fnormal

    F₁=μ(static)•mg

    F₂=μ(kinetic)•mg

  • ?
    Lv 4
    4 years ago

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