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How many mL of 0.136 M NaOH is required to react with the H2SO4 in 10mL of a 0.202 M solution?
the reaction of the two is:
2NaOH + H2SO4 --> Na2SO4 + 2H2O
please help me out any work you can show would be great :)
1 Answer
- 1 decade agoFavorite Answer
first we gotta know: molarity x volume=# of moles
# of mole of H2SO4=0.202x10=2.02mol
# of mole of NaOH needed=2.02/2mol=1.01mol
required volume=1.01/0.136=7.43mL
*the unit of volume should be dm-3
but since they're just a ratio of conversion in this question,
we could simply neglect that.
