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hess law problem, i need some help!?
i understand how its suppose to be done, like make everything on the same side and changes the equations so everything cancels out right. but i just cant figure this one out =[, thanks in advanced.
at 1 atm and 25 degreese celcius, dimamond changes to graphite so slowely that the enthalpy change of the process must be obtaines indirectly. deterimine the change in heat for
C(diamond) ----> C(graphite)
using:
C(diamond) + o2 ----> co2 delta h -395.4 kj
2co2 -----> 2co + o2 delta h 566.0 kj
C(graphite) + o2 ------> co2 delta h -393.5 kj
2co ----> C(graphite) + co2 delta h -172.5 kj
my major hold up is not being able to get the C(diamond) and C(graphite) onto opposite sides to get te problem even started =/.
1 Answer
- Anonymous1 decade agoFavorite Answer
C(diamond) ----> C(graphite)
Multply two of the four equations below by 2 as I have shown and you will find that everything not needed cancels out. Remember to also multiply ∆H by 2.
C(diamond) + O2 ----> CO2 delta h -395.4 kj
2(2CO2 -----> 2CO + O2 delta h 566.0 kj)
C(graphite) + O2 ------> CO2 delta h -393.5 kj
2(2CO ----> C(graphite) + CO2 delta h -172.5 kj)
________________________________________________________
C(diamond) ----> C(graphite) ∆H = -1.9kJ