Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

How would I solve this friction problem?

Ok. I'm given two masses stacked on top of one another with the coefficients of static and dynamic friction between the two blocks and between the bottom block and the floor. I'm also given the dimensions of the blocks (not sure why that matters). I'm given that a force is applied to a corner on the upper block. However, I am not given the mass of either block. How do I solve for the acceleration of each block?

Update:

The force of friction is the coefficient of friction times the normal force, but without mass, how do you get the normal force?

Update 2:

Actually, no the mass is not given and that's not the way the coefficient of friction works.

2 Answers

Relevance
  • 1 decade ago
    Favorite Answer

    Friction is a force that opposes the force being applied against the object. It's usually given in decimal form so that a coefficient of friction of 0 is no friction and a friction coefficient of 1 means the thing can't move at all ( 100% friction ) To solve for the acceleration:

    F = m a. The mass is given. The Force is given. And the coefficient of friction is given, so all you need to do is solve the equation.

  • Anonymous
    4 years ago

    For the gap: s = a million/2 a t^2. The acceleration, a, has a maximum because of the fact the utmost stress that the floor can word on the field is the frictional stress that's F = mu m g, the place mu is the coefficient of static friction. So m a <= mu m g and dividing out the mass m provides a _max = mu g With the gap formula this provides s_max = a million/2 mu g t^2 = a million/2 * 0.24 * 9.80 one m/s^2 * (3.0 s)^2 = 10.6 m

Still have questions? Get your answers by asking now.