C++ help please...logic on how to delete the smallest number does not make sense?

ok so i wrote this program that gives me a bunch of numbers at random and sorts the numbers but now i have to get rid of the smallest number... how do i do that?

here is my code so far

#include <iostream>

#include <cstdlib> //for rand()

#include <ctime> //for time()

using namespace std;

void printarr(int* ,int); //Function prototypes

void sort(int* , int);

double mean(int *, int);

int main()

{

//declare the array

int n;

cout << "Enter the number of elements: ";

cin >> n;

int* a = new int[n];

// puts randoms numbers into the array

for( int i = 0; i < n; ++i)

*(a+i) = (rand() + time(0)) % 100;

cout << "Original array: " << endl;

printarr (a,n);

//Sort it

sort (a,n);

cout << "Sorted array: "<< endl;

printarr(a,n);

//Find the mean

cout << "The mean of the numbers = " << mean (a, n) << endl;

system("PAUSE");

return 0;

}

void sort (int* x, int n)

{

int temp;

int smallest; //location of current smallest element

//find the smallest thing in x[i + 1] to x[n - 1]

for (int i = 0; i< n; ++i)

{

smallest = i;

for (int j = i+1; j < n; ++j)

if (*(x+j) < *(x+smallest))

{

smallest = j;

}

temp = *(x+i);

*(x+i) = *(x+smallest);

*(x+smallest) = temp;

}

}

void printarr (int* a, int n)

{

for(int i = 0; i < n; ++i)

cout << *(a+i) << " ";

cout << endl;

}

double mean (int* x, int n)

{

double sum =0;

for (int i = 0; i < n; ++i)

sum += *(x+i);

return sum / n;

}