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Use this theoretical value to determine the % error in your determination.?
The standard enthalpy of formation of MgO(s) is - 601.8 kJ mole. (remember that your experimental value is for two moles of MgO.)
2 Answers
- Anonymous1 decade agoFavorite Answer
So you take 601.8kJ/mol * 2mol = 1203.6 kJ to be your theoretical value. Then, you take the absolute value of the difference between it and the experimental value, divided by 1203.6 kJ (the theoretical), and multiply by 100% to get the percent error.
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