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Grade 12 Advanced Functions (Trigonometry) Questions?
Hi, I am doing my Trigonometry homework and I have issues with two questions.
1) Determine which is greater, sin(cosx) or cos(sinx)
2) Prove that cos5x = cos^5x -10cos^3xsin^2x + 5cosxsin^4x
3 Answers
- macklerLv 61 decade agoFavorite Answer
1) cos of sin of x is bigger. The proof is
http://www.qbyte.org/puzzles/p109s.html
presuming x is real.
2) cos5x = cos^5x -10cos^3xsin^2x + 5cosxsin^4x
what does ^5x mean?
if its cos(x)^5, then yes, the other two methods work
cos(A + B) = cos A cos B - sin A sin B
cos(3x+2x)=cos3xcos2x-sin3xsin2x
cos3x=cos^3X - 3 cosX sin^2X
and it works from there.
Email me if you need more work/explanation for either,
Mackler
- 1 decade ago
1. cossinx is bigger. Graph it.
2. cos(2x + 3x) Simplify that and keep simplifying using the addition and subtraction formulas
- SaveEnergyNow!Lv 51 decade ago
1) The way to do this is to use sin(x) = cos(pi/2 - x)
which gives you cos(pi/2 - cos x) vs. cos(sin x).
you can then use the identity cos(x) - cos(y) = -2sin(0.5x + 0.5y)sin(0.5x-0.5y)
to prove that cos(sin x) - cos(pi/2 - cos x) > 0 for all x
2) Here you need to use the rule cos(x + y) = cos(x)cos(y) - sin(x)sin(y)
and the rule sin(x+y) = sin(x)cos(y) + cos(x)sin(y)
with x = x and y = 4x