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Grade 12 Advanced Functions (Trigonometry) Questions?

Hi, I am doing my Trigonometry homework and I have issues with two questions.

1) Determine which is greater, sin(cosx) or cos(sinx)

2) Prove that cos5x = cos^5x -10cos^3xsin^2x + 5cosxsin^4x

3 Answers

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  • 1 decade ago
    Favorite Answer

    1) cos of sin of x is bigger. The proof is

    http://www.qbyte.org/puzzles/p109s.html

    presuming x is real.

    2) cos5x = cos^5x -10cos^3xsin^2x + 5cosxsin^4x

    what does ^5x mean?

    if its cos(x)^5, then yes, the other two methods work

    cos(A + B) = cos A cos B - sin A sin B

    cos(3x+2x)=cos3xcos2x-sin3xsin2x

    cos3x=cos^3X - 3 cosX sin^2X

    and it works from there.

    Email me if you need more work/explanation for either,

    Mackler

  • 1 decade ago

    1. cossinx is bigger. Graph it.

    2. cos(2x + 3x) Simplify that and keep simplifying using the addition and subtraction formulas

  • 1 decade ago

    1) The way to do this is to use sin(x) = cos(pi/2 - x)

    which gives you cos(pi/2 - cos x) vs. cos(sin x).

    you can then use the identity cos(x) - cos(y) = -2sin(0.5x + 0.5y)sin(0.5x-0.5y)

    to prove that cos(sin x) - cos(pi/2 - cos x) > 0 for all x

    2) Here you need to use the rule cos(x + y) = cos(x)cos(y) - sin(x)sin(y)

    and the rule sin(x+y) = sin(x)cos(y) + cos(x)sin(y)

    with x = x and y = 4x

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