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Chemistry help! Liters, temp, pressure given?
A gas sample occupies a volume of 18.86 L when the temperature is 35.2 °C and the pressure is 735.5 torr. How many moles of gas are in the sample?
Can somebody explain how to find the answer?
4 Answers
- 1 decade agoFavorite Answer
To answer this question you use the formula PV = nRT. Where:
P = Pressure in atm
V = Volume in L
n = moles
R = 0.08206 L*atm/mol*K (gas constant)
T = temperature in K
So what you have to do here is frist change torr to atm and degrees Celsius to Kelvin.
There are 760 torr in 1 atm. So you divide:
735.5 torr * 1 atm / 760 torr = 0.97 atm
Then to change celsius to kelvin you just add 273
35.2 + 273 = 308.2K
Then you move the formula around so you are solving for n
n = PV / RT
Then you can just plug in the numbers:
n = (0.97atm)(18.86L) / (0.08206 L*atm / mol*K)(308.2K)
Everythin cancels each other out except for moles.
n = 0.723 moles
So your answer is 0.723 moles =]
Hope that helped!!!
Source(s): Chemistry Major - Robert DLv 71 decade ago
Use the ideal gas equation: pV = nRT
p = pressure in atmospheres = 735.5 torr/760.0 torr = 0.9677 atm
V = volume in liters = 18.86 L
n = moles
R = 0.08206 L*atm/K*mol
T = 35.2 °C + 273.2 = 308.4 K
n = pV/RT = (0.9677 atm)(18.86 L)/(0.08206 L*atm/K*mol)(308.4 K) = 0.7212 mol gas in the sample
Hope this helps
- 1 decade ago
Use the ideal gas law:
P V = n R T
n = P V / R T
Change units of P = 735.5 / 760 = 0.967 atm
and T = 35.2 + 273 = 308.2 K
V = 35.2 Litres
R = 0.0814
n = 0.967 x 35.2 / 0.08314 x 308.2 = 1328.39 gmoles
- Anonymous1 decade ago
PV=nRT