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Chemistry help! Liters, temp, pressure given?

A gas sample occupies a volume of 18.86 L when the temperature is 35.2 °C and the pressure is 735.5 torr. How many moles of gas are in the sample?

Can somebody explain how to find the answer?

4 Answers

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  • 1 decade ago
    Favorite Answer

    To answer this question you use the formula PV = nRT. Where:

    P = Pressure in atm

    V = Volume in L

    n = moles

    R = 0.08206 L*atm/mol*K (gas constant)

    T = temperature in K

    So what you have to do here is frist change torr to atm and degrees Celsius to Kelvin.

    There are 760 torr in 1 atm. So you divide:

    735.5 torr * 1 atm / 760 torr = 0.97 atm

    Then to change celsius to kelvin you just add 273

    35.2 + 273 = 308.2K

    Then you move the formula around so you are solving for n

    n = PV / RT

    Then you can just plug in the numbers:

    n = (0.97atm)(18.86L) / (0.08206 L*atm / mol*K)(308.2K)

    Everythin cancels each other out except for moles.

    n = 0.723 moles

    So your answer is 0.723 moles =]

    Hope that helped!!!

    Source(s): Chemistry Major
  • 1 decade ago

    Use the ideal gas equation: pV = nRT

    p = pressure in atmospheres = 735.5 torr/760.0 torr = 0.9677 atm

    V = volume in liters = 18.86 L

    n = moles

    R = 0.08206 L*atm/K*mol

    T = 35.2 °C + 273.2 = 308.4 K

    n = pV/RT = (0.9677 atm)(18.86 L)/(0.08206 L*atm/K*mol)(308.4 K) = 0.7212 mol gas in the sample

    Hope this helps

  • 1 decade ago

    Use the ideal gas law:

    P V = n R T

    n = P V / R T

    Change units of P = 735.5 / 760 = 0.967 atm

    and T = 35.2 + 273 = 308.2 K

    V = 35.2 Litres

    R = 0.0814

    n = 0.967 x 35.2 / 0.08314 x 308.2 = 1328.39 gmoles

  • Anonymous
    1 decade ago

    PV=nRT

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