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Chem help again! Involves STP?
A sample of a gas was isolated in a gas containment bulb on a manifold used in this type work. The volume of the bulb was 1.524 L. The temperature was 28.40 °C, and the manifold pressure was 637.6 torr. What volume, in liters, would this gas sample occupy at STP?
Please explain
1 Answer
- 1 decade agoFavorite Answer
All right so for this question you would use P1V1/T1 = P2V2/T2.
Your initial values are all given.
P1 = 637.6 torr
V1 = 1.524 L
T1 = 28.40C
When using this equation you need the pressure in atm, volume in L, and temperature in K. So we're good with the volume but we need to fix pressure and temperature.
637.6 torr * 1 atm / 760 torr = 0.839 atm
28.40 +273 = 301.4K
Now for the final values, they are telling us to use STP (Standard Temperature and Pressure) which is:
T = 273 K
P = 1 atm
So we manipulate the formula to solve for V2
V2 = P1V1T2 / T1P2
Now we just plug in. Be careful with the initial and final volume, they can get a bit confusing.
V2 = (0.839 atm)(1.524 L ) (273K) / (301.4 K ) ( 1 atm) = 1.158 L
Hope that helped!!
Source(s): Chemistry Major
