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Chemistry help involving mixture and its partial pressure?
A mixture of 5.00 mol of neon and 3.00 mol of nitrogen occupy a volume of 36.0 L in a vessel where the total pressure is 6.00 atm. The partial pressure of the neon in the container is...
2 Answers
- 1 decade agoFavorite Answer
Okay here're some basics first (if you understand these just skip to the bottom).
Moles = amount of a substance. Just like we can measure grams to measure amount, moles is another such measure except that it takes the actual weight (in grams) and divides by the substance's atomic/molecular weight - kinda makes everything standardised.
Partial pressure is just the fraction of the total pressure that a certain gas produces. (Every gas produces a pressure). So if we know the fraction of *amounts* of the gases in a mixture, we can still find the fraction of the *pressure* of a certain gas like so:
Partial pressure of neon = fraction of neon in mixture x total pressure
Fraction of neon = 5.00 / (5.00 + 3.00) = 5/8
So partial pressure of Neon = 5/8 x 6.00 atm
= 3.75 atm.
- 1 decade ago
Partial pressure of a gas = (number of gas moles/number of mixture moles) x total pressure
partial pressure of Neon = (5/8) x 6 = 3.75 atm