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6. a cell phone company offers a contract for which the cost C, in dollars, of t minutes of telephoning?

is given by C=0.25(t-400)+47.95, where it is assumed that t>=400 minutes. What times will keep costs between $86.20 and $114.95?

23. solve and grapgh the compound inequity

2x-14<=-7 or x-6>=1

the solution of the compound inequality is {x|x<=__ or x>=__}?.

3 Answers

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  • 1 decade ago
    Favorite Answer

    0.25(t - 400) + 47.95 = 86.20

    0.25(t - 400) = 38.25

    t - 400 = 153

    t = 553

    0.25(t - 400) + 47.95 = 114.95

    0.25(t - 400) = 67

    t - 400 = 268

    t = 668

    Answer: 553 ≤ t ≤ 668 or Between 553 and 668

    -----------

    2x - 14 ≤ - 7

    2x ≤ 7

    x ≤ 7/2 or 7/2 ≥ x

    x - 6 ≥ 1

    x ≥ 7

    Answer: 7/2 ≥ x ≥ 7???????

  • 1 decade ago

    C=0.25(t-400)+47.95

    86.20 = 0.25(t-400)+47.95

    (86.20 - 47.95)/.25 = t - 400

    t = (86.20 - 47.95)/.25 + 400

    = 553 mins

    114.95 = 0.25(t-400)+47.95

    (114.95 - 47.95)/.25 = t -400

    t = (114.95 - 47.95)/.25 + 400

    = 668 mins

    23) 2x -14 <= -7

    2x<= -7 +14

    2x <- 7

    x <- 7/2

    x -6 >= 1

    x >= 7

    {x|x<= -7/2 or x>= 7}

    Graph the compound inequality gives two regions to the left an equal to -7/2 and to the right or equal

    to 7.

  • 1 decade ago

    For the first one, just set C = to the wanted costs:

    86.20 = 0.25(t-400)+47.95 and 114.95 = 0.25(t-400)+47.95

    and solve for t. Give the answer like this: (minutes for first part) <= t <= (minutes for last part). I'll let you put it in the calculator!

    For the second one,

    2x - 14 <= -7

    2x <= -21

    x<= -21/2

    x- 6 >= 1

    x >= 7

    Therefore, {x|x<= -21/2 or x>= 7}

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