Please help: solve the system of equations: 5x-2y=44 when x=-4y?

use substituition

5(-4y)-2y=44

-20y-2y=44

-22y=44

y=-2

x=-4y

x=-4(-2)

x=8

answer y=-2 x=8

5x - 2y = 44

When x = -4y,

5(-4y) - 2y = 44

-20y - 2y = 44

-22y = 44

y = -2

Substitute y = -2 into the equation.

5x - 2(-2) = 44

5x + 4 = 44

5x = 40

x = 8

Thus, x = 8 and y = -2.

you can substitute x=-4y into the first equation. that is,

5(-4y)-2y=44

-20y-2y=44

-22y=44

y=(44/-22)

y=-2

now that you have what y is equal to you can substitute that back into the second equation and solve for x. that is,

x=-4(-2)

x=8.

therefore if 5x-2y=44 and x=-4y then x=8 and y=-2.

We can solve this using substitution. Take the first equation: 5x-2y=44. Since x=-4y, we'll put -4y everywhere we see x, giving us

5(-4y)-2y=44

-20y-2y=44

-22y=44

y=-2

Now we know the value of y, so we can take the second equation, x=-4y, and plug in -2 everywhere we see y.

x=-4y

x=-4(-2)

x=8

So our solution is x=8, y=-2.

it will help if you put it this format:

5x-2y=44

x=-4y

______

So i am going to substitute x in the first equation with -4y since it is proven in the second equation.

5(-4y)-2y=44

-20y-2y=44

-22y=44

y=-2

Now, we know what is the value of y, but we still need the value of x, so we plug in y with -2 to find x.

5x-2(-2)=44

5x+4=44

5x=40

x=8

Check (see if we did everything right)

5(8)-2(-2)=44

40+4=44 ~ correct!

8=-4(-2) ~ correct!

ok...this makes more sense and the other guys are correct except in a system of equations you still have to solve for x also so if y = -2 then x = -4y = -4(-2) = 8

x= -4y put this value in the given eq

5x-2y = 44

5(-4y)-2y =44

-20y-2y = 44

-22y =44

y=-2

and x=-4y = -4*-2 = 8

Ans x=8 and y =-2

Good luck !!!

5x - 2y = 44 when x = -4y

5(-4y) - 2y = 44

-20y - 2y = 44

-22y = 44

y = -2

- 20 y - 2 y = 44

- 22 y = 44

y = - 2

x = 8

5x-2y=44

5(-4y)-2y=44

-20y-2y=22

-22y=44

y=44/-22

y=-2

x=-4(-2)

x=8

answer: y=-2, x=8