Find the value of f(0)of the function f(x) = 3x^2 + 2x + 5?

f(x) = 3x^2 + 2x + 5

f(0) = 3(0)^2 + 2(0) + 5

= 3(0) + 2(0) + 5

= 0 + 0 + 5

= 5

Answer: B. f(0) = 5

B, f(0) = 5

B. f (0) = 5

f(0) = 5

value of f(0)of the function f(x) = 3x^2 + 2x + 5

means, substitute the value of x=0 in the given equation of the function f(x)

i.e., f(x)= f(0) = 3. (0)^2 + 2.(0) +5

= 3.(0) + 0 + 5

= 0 + 0 + 5 = 5

Hence, f(x) = f(0) = 5

i.e.,the answer is ---> B . f(0) = 5

It says f(0) so substitute 0 for x in your equation and the only thing you're left with is +5

:-)

✐Explanation✐

Substitute x with 0 and simplify. f(0) = 5

Another way to solve this:

If x-coordinate is zero, then the solution is y-intercept. Think that way and solve this problem.

f(x)=3(x)^2+2(x)+5

f(0)=2(0)^2+2(0)+5

=0+0+5

f(0)=5