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very hard math question, well to me?
can anybody solve this hard math question
3 to the 8th power times 6 to the fifth power over 3 to the 10 power times 6 to the third power
the answer choices are 4,2,8,6
im not cheating because its a interim and the teacher gave it back to redo them to study
13 Answers
- mohanrao dLv 71 decade agoFavorite Answer
(3^8)*(6^5)
___________
(3^10)*(6^3)
= 3^(8 - 10)*6^(5 - 3)
= 3^(-2)*6^2
= (6^2) / (3^2)
= 36 / 9
= 4
- TompLv 71 decade ago
When you multiply like values you add the exponents. Similarly, when dividing, you subtract exponents.
For example, suppose you want to multiply a^5 times a^3 (the '^n' notation means 'to the power of n)
a^5 x a^3 = (a x a x a x a x a ) x (a x a x a)
= a x a x a x a x a x a x a x a
= a^8
Also a^5 divided by a^3 = (a x a x a x a x a ) / (a x a x a)
= (a x a) x (a x a x a) /(a x a x a)
= (a x a) x 1
= (a x a)
= a^2
Furthermore, since a^0 = 1 for all numbers a
1/a = a^0 / a^1
= a^(0-1)
= a^(-1)
Similarly, for any power k
1/a^k = a^(-k)
So we could have
(a x a x a x a x a ) / (a x a x a)
= a^5 x a (-3)
= a^(5-3)
= a^2
One more point: if a = mn (understood to mean m x n), then
a^k = (mn)^k = m^k x n^k
So, armed with this knowledge and knowing that 6 equals 3 x 2, your problem
3 to the 8th power times 6 to the fifth power over 3 to the 10 power times 6 to the third power
becomes
(3^8 x 6^5) / (3^10 x 6^3) = (3^8 x (3 x 2)^5) / (3^10 x (3 x 2)^3)
= (3^8 x 3^5 x 2^5) / (3^10 x 3^3 x 2^3)
= (3^(8+5) x 2^5) / (3^(10+3) x 2^3)
= (3^13 x 2^5) / (3^13 x 2^3)
= 3^13 x 2^5 x 3^(-13) x 2(-3)
= 3^(13-13) x 2^(5-3)
= 3^0 x 2^2
= 1 x 2^2
= 1 x 4
= 4
It's a bit drawn out, but it's better that you know how to solve such problems rather than simply giving you the answer.
It's not particularly difficult; it's just a matter of knowing the mechanics of operating on exponents. Once you get the idea (as demonstrated above), it will be a breeze!
- 1 decade ago
Answer = 4
Use a calculator or simplify the following
(3^8 x 6^5) / (3^10 *6^3) = (3^[8-10]) x (6^[5-3]) = 3^(-2) x 6^2 = [1/3^2] x 6^2
= 1/9 x 6 x 6
= 36/9
=4
- 1 decade ago
(3^8)(6^5)/((3^10)(6^3))
When dividing with a common base, subtract the exponents to get:
(3^(8-10)) (6^(5-3))
which simplifies to:
3^-2 * 6^2
negative exponents mean: a^-n = 1/a^n, so 3^-2=1/3^2 which is 1/9
6^2 = 36 so:
36 (1/9) =4
So the answer is 4
- Ray SLv 71 decade ago
____________________________
3⁸6⁵ 6⁵⁻³ 6²
——– = ——– = —— = (6 ̸ 3)² = 2² = 4
3¹⁰6³ 3¹⁰⁻⁸ 3²
___________________________________
- SPBLv 61 decade ago
3^8 * 6^5 / 3^10 * 6^3
simplify
33333333 * 66666 / 3333333333 * 666 cancel out the 3's and 6's to get
66 / 33 or
6^2/3^2 = 36/9 = 4
- HPVLv 71 decade ago
(3^8 x 6^5 ) / (3^10 x 6^3) = (3^8 / 3^10) x (6^5 / 6^3) = (3^-2)(6^2) = (1 / 3^2)(6^2) = (1/9)(36) = 4