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hard test question that i didn't get?
the equation B=1+3n tells the number of beams required to build a frame of n sectoins. how many sections can be built with 79 beams?
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- Anonymous1 decade agoFavorite Answer
B represents beams. If you have the number of beams, 79, just substitute it in the equation to solve for the number of sections, n, that required that many beams.
B = 1 + 3n
79 = 1 + 3n
78 = 3n
n = 26
26 sections.
- 1 decade ago
B is the number of beams. So we just set 79=1+3n.
That is, 78=3n. So n= 78/3=26 sections
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