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what is the answer of this equation? -1=x^(6 )_5x^(3 )?

2 Answers

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  • 1 decade ago
    Favorite Answer

    x^6 - 5x^3 = -1

    => x^6 - 5x^3 + 1=0

    => let x^3 = y

    => y^2 - 5y+1 = 0

    we know that for quadratic equation ax^2+bx+c=0 ,

    x is given by x = (-b(+/-)sq rt (b^2-4ac))/2ac

    so y=[5(+/-)sq rt(25 - 4)]/2

    y=[5(+/-)sq rt(21)]/2

    x^3= [5(+/-)sq rt(21)]/2

    x = {[5(+/-)sq rt(21)]/2}^1/3

  • 1 decade ago

    -1=x^6 - 5x^3

    x=(((21)^(1/2)+5)^(1/3)*2^(2/3))/2

    x=1.68584 or .593175

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