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Given the equation H2O (l) → H2O (g) △Hrxn = 40.7 kJ at 100degreesC?
Given the equation
H2O (l) → H2O (g) △Hrxn = 40.7 kJ at 100degreesC
Calculate the mass of liquid water (in grams) at 100oC that can converted to vapor by absorbing 2.400 kJ of heat.
how would i go about solving this?
thanks for the help.
1 Answer
- Steve OLv 71 decade agoFavorite Answer
find moles:
2.400 kJ @ 40.7 kJ/mole = 0.05897 moles of water
find grams, using molar mass:
0.05897 moles of water @ 18.015 g/mol =
your answer is:
1.06 grams of water
==========================
unless "2.400 kJ of heat."
was supposed to be 2,400 kJ of heat.
in which case your answer would be 1060 grams of water
